In Class 11 Final Exams there will be Case studies and Passage Based Questions will be asked, So practice these types of questions. Study Rate is always there to help you. Free PDF Download of CBSE Class 11 Physics Chapter 4 Case Study and Passage Based Questions with Answers were Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 11 Physics Motion In A Plane to know their preparation level.

In CBSE Class 11 Physics Paper, There will be a few questions based on case studies and passage-based as well. In that, a paragraph will be given, and then the MCQ questions based on it will be asked.

Motion In A Plane Case Study Questions With answers

Here, we have provided case-based/passage-based questions for Class 11 PhysicsChapter 4 Motion In A Plane

Case Study/Passage-Based Questions

Case Study 1:

When an object follows a circular path at a constant speed, the motion of the object is called uniform circular motion. The word "uniform" refers to the speed, which is uniform (constant) throughout the motion. Suppose an object is moving with uniform speed v in a circle of radius R Since the velocity of the object is changing continuously in direction, the object undergoes acceleration. Let us find the magnitude and the direction of this acceleration. Thus, the acceleration of an object moving with speed v in a circle of radius R has a magnitude V2/R and is always directed towards the centre. This is why this acceleration is called centripetal acceleration (a term proposed by Newton). A thorough analysis of centripetal acceleration was first published in 1673 by the Dutch scientist Christiaan Huygens (1629-1695) but it was probably known to Newton also some years earlier. "Centripetal" comes from a Greek term which means 'centre-seeking'. Since v and R are constant, the magnitude of the centripetal acceleration is also constant. However, the direction changes pointing always towards the centre. Therefore, a centripetal acceleration is not a constant vector. We can express centripetal acceleration ac in terms of angular speed as

ac = ω2R

The time taken by an object to make one revolution is known as its time period T and the number of revolution made in one second is called its frequency v (=1/T). However, during this time the distance moved by the object iss= 2πR. Therefore,v= 2πR/T=2πRv In terms of frequency n, we have

ω = 2πv

v= 2πRv

ac= 4π2 v 2 R

1) SI unit of angular velocity is

a) Rev/sec

b) m/s

c) m/s2

d) None of these

Answer: a) Rev/sec

2) A centripetal acceleration is not a constant vector. True or false?

a) True

b) False

Answer: a) True

3) Define Uniform circular motion

Answer: When an object moves in a circular path with uniform speed, its motion is called uniform circular motion.

4) What is meaning of word centripetal?

Answer: "Centripetal" comes from a Greek term which means 'centre-seeking' i.e. always directed towards centre of a circle.

5) What is centripetal acceleration? Give its relation with angular velocity

Answer: Acceleration of particle performing uniform circular motion which is always directed towards centre of a circle is called centripetal acceleration. We can express centripetal acceleration ac in terms of angular speed as

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